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Question

Given the ionic equivalent conductivities for the following ions :

λeqK=73.5cm2ohm1eq1

λeqAl3+=189cm2ohm1eq1

λeqSO24=85.8cm2ohm1eq1

The Λeq for potash alum (K2SO4.Al2(SO4)3.24H2O) is :


A
245.92
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B
348.3
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C
368.2
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D
108.52
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Solution

The correct option is C 245.92

(Eq = Charge on the ion/Total charge)

[K]=18mol×2=14mol=14Eq

[Al3+]=68=34Eq

[SO24]=88=1Eq


Now,

ΛeqK2SO4.Al2(SO4)3.24H2O

=λeq(K)+λeq(Al3+)+λeq(SO24)

14×73.5+189×34+85.8×1

18.375+141.75+85.8

245.92


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