Question

Given the polymers, A= nylon-6, 6, B= buna-S, C = polythene. Arrange these in increasing order of their intermolecular force (lower to higher).

• A. $A<B<C$
• B. $B<A<C$
• C. $B<C<A$
• D. $C<B<A$

Answer 1

The correct option is C $B<C<A$

Different types of polymers have different intermolecular forces of attraction. Elastomer or rubbers have the weakest while fibers have the strongest intermolecular forces of attraction. Plastics have intermediate intermolecular forces of attraction. Hence, the increasing order of the intermolecular forces of the given polymers is as follows:
Buna – S (B) < polythene (C) < Nylon 6, 6 (A)