Question

Given the polymers
$A=$ Nylon 6,6; $B=$ Buna-S; $C=$ Polythene.

Arrange these in decreasing order of their intermolecular forces.

• A. $A>B>C$
• B. $B>C>A$
• C. $B<C<A$
• D. $C<A<B$

Answer 1

The correct option is A $A>B>C$

Polyamides are having polar bond so, they are strongest. Between polyethylene and Buna-S, Buna-S has a larger surface area, so, it will be more.

So the order is $C<B<A$.