Given the standard oxidation potentials- Fe Fe2-aq- Fe3-aq- FeFeOH2FeOH3It is easier to oxidise Fe2- to Fe3- in-

The correct option is B alkaline medium E_Fe^2+/ Fe^3+^∘ is positive in alkaline solution, therefore, it is easier to oxidise Fe^2+ to Fe^3+ in ...

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Calculating Oxidation Number

Given the sta...

Question

Given the standard oxidation potentials,
$F e + 0.4 V - --- \to F e^{2 +} (a q .) - 0.8 V - --- \to F e^{3 +} (a q .)$
$F e + 0.9 V - --- \to F e (O H)_{2} 0.6 V - -- \to F e (O H)_{3}$
It is easier to oxidise $F e^{2 +}$ to $F e^{3 +}$ in:

acidic medium

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alkaline medium

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neutral medium

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both in acidic and alkaline mediums

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Solution

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Similar questions

How to balance this by oxidation number method $H_{2} O_{2} (a q) + F e^{2} (a q) + ⟶ F e^{3} (a q) + H_{2} O (l)$ [in acidic medium)

3.1

F e^{3 +} (a q)

I^{-} (a q)

A g^{+} (a q)

C u (s)

F e^{3 +} (a q)

B r^{-} (a q)

A g (s)

F e^{3 +} (a q)

B r_{2} (a q)

F e^{2 +} (a q)

E_{F e (s) / F e^{2 +} (a q)}^{0} = 0.44 V

E_{F e^{2 +} (a q) / F e^{3 +} (a q)}^{0} = - 0.77 V

F e (s) + 2 F e^{3 +} (a q) \to 3 F e^{2 +} (a q)

E_{F e^{3 +} / F e}^{0} = 0.036 V, E_{F e^{2 +} / F e}^{0} = - 0.439 V

F e^{3 +} (a q) + e^{-} \to F e^{2 +} (a q)

The oxidation half reaction for following reaction is

Fe²⁺(aq) + Cr₂O₇^2-(aq) → Fe³⁺ (aq) + Cr³⁺(aq)

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