Given this reaction that occurs in plants: $6 C O_{2} + 6 H_{2} O \to C_{6} H_{12} O_{6} + 6 O_{2}$ . If 54 grams of water are consumed by the plant, how many grams $C_{6} H_{12} O_{6}$ (molar mass = 180) can be made? Assume an unlimited supply of $C O_{2}$ .

54 g

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180 g

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540 g

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3 g

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90 g

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Solution

The correct option is E 90 g
The molar mass of water is 18 g/mol.
The mass of water is 54 g.

The number of moles of water $= \frac{54 g}{18 g / m o l} = 3 m o l$ .

6 moles of water gives one mole of glucose.

3 moles of water will give $\frac{3}{6} \times 1 = 0.5$ moles of glucose.

The molar mass of glucose is 180 g/mol.

The mass of glucose is $0.5 m o l \times 180 g / m o l = 90 g$ .

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Similar questions

C_{6} H_{12} O_{6} + 6 O_{2} \to 6 C O_{2} + 6 H_{2} O

C_{6} H_{12} O_{6} + 6 O_{2} \to 6 C O_{2} + 6 H_{2} O

C_{6} H_{12} O_{6}

1 g c m^{- 3}

6 C O_{2} + 6 H_{2} O

⟶

C_{6} H_{12} O_{6} + 6 O_{2}

CO₂ + H₂O → C₆H₁₂O₆ + O₂ + H₂O

Is the given equation correct? If not, correct it.

Observe the reactions given below and choose the correct option.

Reaction 1: $C_{6} H_{12} O_{6} + 6 O_{2}$ $⟶$ $6 C O_{2} + 6 H_{2} O + E n e r g y$

Reaction 2: $6 C O_{2} + 6 H_{2} O$ $L i g h t - --- \to$ $C_{6} H_{12} O_{6} + 6 O_{2}$

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