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Question

Given three resistors of 2 Ω,4 Ω and 6 Ω, what will be the minimum equivalent resistance that can be obtained through their various permutations?
  1. 1.0909 Ω
  2. 0.9167 Ω
  3. 0.8125 Ω
  4. 1 Ω


Solution

The correct option is A 1.0909 Ω
Given, R1=2 Ω
R2=4 Ω
R3=6 Ω
Let R be the equivalent resistance.
When you connect a group of resistors in parallel, the value of effective resistance will be smaller than the value of smallest resistor of the group.
We know, for parallel combination,
1R=1R1+1R2+1R3
1R=12+14+16

1R=6+3+212

R=1211 Ω=1.0909 Ω is the minimum equivalent resistance we can get from the three given resistors.
 

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