Given ABC - PQR- if ABPQ-13- then find ar ABCar PQR-

ABC∼ PQR ABPQ=13 ar ABCar PQR= ( ABPQ )^2= ( BCQR )^2= ( ACPR )^2 ar ABCar PQR= (13 #160; )^2=19 ...

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Relation between Areas and Sides of Similar Triangles

Given ABC ∼...

Question

Given $△ A B C \sim △ P Q R$ , if $\frac{A B}{P Q} = \frac{1}{3}$ , then find $\frac{a r (△ A B C)}{a r (△ P Q R)}$ .

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Solution

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△ A B C \sim △ P Q R

m^{2}

m^{2}

△ A B C \sim △ P Q R

\frac{a r (△ A B C)}{a r (△ P Q R)} = \frac{A C^{2}}{P Q^{2}}

△ A B C \sim △ P Q R,

\frac{a r (A B C)}{a r (P Q R)} = \frac{9}{4}

A B = 18

c m

B C = 15

c m

Q R

Δ A B C \sim Δ P Q R,

\frac{A B}{P Q} = \frac{1}{3},

\frac{a r Δ A B C}{a r Δ P Q R}

Δ A B C \sim Δ P Q R

\frac{A B}{P Q} = \frac{1}{3}

\frac{a r Δ A B C}{a r Δ P Q R}

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