Given two 4-digit numbers $a b c d$ and $d c b a$ . If $a + d = b + c = 7$ , then their sum is not divisible by

7

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11

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101

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111

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Solution

The correct option is B $111$
Given two 4-digit numbers are $a b c d$ and $d c b a$
$a + d = b + c = 7$
$a b c d$
$+$ $d c b a - ----- -$
$7777$
The number $7777$ is divisible by $7, 11$ and $101$ but not divisible by $111$ .
Hence, option D is correct.

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Q. A four digit number abcd is divisible by 11 if only
A.(a+b)-(c+d) is divisible by 11
B.(a-c)-(b-d) is divisible by 11
C.(a-c)-(b+d) is divisible by 11
D.(b+d)-(a+c) is divisible by 11
The coerrect answer is 'D' but how?

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Q. A number consists of

7

digits whose sum is

59

; prove that the chance of its being divisible by

11

\frac{4}{21}

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Given two 4-digit numbers abcd and dcba. If a+d=b+c=7, then their sum is not divisible by

The correct option is B 111Given two 4-digit numbers are abcd and dcbaa+d=b+c=7 a b c d+ d c b a––––––– 7 7 7 7The number 7777 is divisible by 7,11 and 101 but not divisible by 111.Hence, option D is correct.

Given two 4-digit numbers $a b c d$ and $d c b a$ . If $a + d = b + c = 7$ , then their sum is not divisible by

The correct option is B $111$
Given two 4-digit numbers are $a b c d$ and $d c b a$
$a + d = b + c = 7$
$a b c d$
$+$ $d c b a - ----- -$
$7777$
The number $7777$ is divisible by $7, 11$ and $101$ but not divisible by $111$ .
Hence, option D is correct.