Question

Given two independent events A and B such that P(A) = 0.3, P(B) = 0.6 Find
P(A and not B)

Answer 1

It is given that P(A) = 0.3 and P(B) = 0.6
Also, A and B are independent events.
$P\left(AandnotB\right)=P(A\cap B^{\prime })=P\left(A\right)\times P\left(B\right)$
$(\because$ A and B are independent $\therefore$ A and B' are also independent)
$=\left(0.31\right)[1-P(B\left)\right]=\left(0.3\right)(1-0.6)=0.3\times 0.4=0.12$