Question

Given two independent events A and B such that $P\left(A\right)=0.3,$ $P\left(B\right)=0.6$ then, find $P\left(A\cap B\right)$

Answer 1

Since $A$ and $B$ are Independedent Events

$P(A\cap B)$=$P\left(A\right)\ast P\left(B\right)$,

$\Rightarrow$ $P(A\cap B)=0.18$