Question

Given: $v=0.6-0.3t$ (in SI units). The acceleration is

• A. $-0.3{\text{ms}}^{-2}$
• B. $0.6{\text{ms}}^{-2}$
• C. $2.4{\text{ms}}^{-2}$
• D. $3.6{\text{ms}}^{-2}$

Answer 1

The correct option is A $-0.3{\text{ms}}^{-2}$

$a=dv/dt$ (where $v$ is the velocity)
Acceleration $=\frac{d}{dt}(0.6-0.3t)$
$\Rightarrow a=-0.3{\text{ms}}^{-2}$