Question

In the graph given below, what is the acceleration at $t=1s$?

• A. $0\text{m}{\text{s}}^{-2}$
• B. $2\text{m}{\text{s}}^{-2}$
• C. $2.5\text{m}{\text{s}}^{-2}$
• D. $10\text{m}{\text{s}}^{-2}$

Answer 1

The correct option is D $10\text{m}{\text{s}}^{-2}$

Since the velocity is increasing uniformly between $0$ to $2$ seconds, acceleration is constant and it is equal to the slope of the line.
Here, let us suppose $(x_1,y_1)=(0,0)$ and $(x_2,y_2)=(1,10)$

The slope of the line = acceleration
$=\frac{y_2-y_1}{x_2-x_1}=\frac{10-0}{1-0}=10m{s}^{-2}$

Hence, acceleration at $t=1s$ is $10m{s}^{-2}$.