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Van der Waal's Equation - Derivation

Given van der...

Question

Given van der Waals constant for $N H_{3}, H_{2}, O_{2} a n d C O_{2}$ are respectively 4.17, 0.244, 1.36 and 3.59, which one of the following gases is most easily liquefied?

C O_{2}

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N H_{3}

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O_{2}

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H_{2}

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Solution

The correct option is B $N H_{3}$
van der Waal constant ′a′ , signifies intermolecular forces of attraction.

Higher is the value of ′a′ , easier will be the liquefaction of gas.
Hence, option (b) is correct.

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Similar questions

N H_{3}

H_{2}

O_{2}

C O_{2}

b a r L^{2} m o l^{- 2}

N H_{3}

H_{2}

O_{2}

C O_{2}

b a r L^{2} m o l^{- 2}

^{'} a^{'}

a

N H_{3} = 4.17, C O_{2} = 3.59, S O_{2} = 6.71 & C l_{2} = 6.49

a

N H_{3} = 4.17, C O_{2} = 3.59, S O_{2} = 6.71 & C l_{2} = 6.49

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