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Liquefaction of Gases and Critical Constants

Given van der...

Question

Given van der Waals constants 'a' for $N H_{3}$ , $H_{2}$ , $O_{2}$ and $C O_{2}$ are respectively 4.17, 0.244, 1.36 and 3.59 $b a r L^{2} m o l^{- 2}$ , which one of the following gases can be the most easily liquefied?

O_{2}

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H_{2}

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N H_{3}

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C O_{2}

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Solution

The correct option is C $N H_{3}$
The van der waal constant ‘a’, signifies intermolecular forces of attraction
Higher the value of ‘a’, easier will be the liquefaction of the gas

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Similar questions

N H_{3}

H_{2}

O_{2}

C O_{2}

b a r L^{2} m o l^{- 2}

N H_{3}, H_{2}, O_{2} a n d C O_{2}

a

O_{2}, N_{2}, N H_{3}, a n d C H_{4}

2.253 L^{2} a t m m o l^{- 2}

^{'} a^{'}

a

N H_{3} = 4.17, C O_{2} = 3.59, S O_{2} = 6.71 & C l_{2} = 6.49

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