Given x2+7x+12=0. Then factors of x2+7x+12 are :
Which of the following are the factors of x2+7x+12 ?
(x2−4x−21)=?
(a) (x−7)(x−3)
(b) (x+7)(x−3)
(c) (x−7)(x+3)
(d) None of these
Given
(x2−5x+6)(x2−7x+12)=(x2−x−6)(x2+7x+10), then the value of x is