Glutamic acid H 2 N - CH CH 2 CH 2 COOH - COOHN has pK a 1- COOH -2-2- pKa 2 R group COOH -4-3- Theisoelectric point of glutamic acid isA- 5-9B- 7C- 3-2D- 10-2

The correct option is C 3.2H_3 +N Cationic formCH_2CH_2COOH|CH COOH On neutralisation1st ionization⟶ H_3 +N CH_2CH_2COOH|CH COO^ 2nd ionization⟶ H_3 + ...

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Byju's Answer

Standard XII

Chemistry

Applications of Colloids

Glutamic acid...

Question

Glutamic acid $H_{2} N - C H (C H_{2} C H_{2} C O O H) - C O O H N$ has $p K_{a 1} (α - C O O H) = 2.2, p K a 2 (R g r o u p C O O H) = 4.3$ . The isoelectric point of glutamic acid is

5.9

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10.2

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3.2

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Solution

The correct option is D 3.2
$H_{3} + N - C H | C H_{2} C H_{2} C O O H C a t i o n i c f o r m - C O O H O n n e u t r a l i s a t i o n ⟶ 1 s t i o n i z a t i o n H_{3} + N - C H | C H_{2} C H_{2} C O O H - C O O^{-} ⟶ 2 n d i o n i z a t i o n H_{3} + N - C H | C H_{2} C H_{2} C O O^{-} - C O O^{-}$

$I s o e l e c t r i c p o i n (p I) = \frac{p K_{a_{1}} + p K_{a_{3}}}{2}$
$\frac{2.2 + 4.3}{2} = 3.25$

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Glutamic acid H2N−CH(CH2CH2COOH)−COOHN has pKa1(α−COOH)=2.2,pKa2(R group COOH)=4.3. The isoelectric point of glutamic acid is

The correct option is D 3.2H3+N−CH|CH2CH2COOHCationic form−COOHOn neutralisation⟶1st ionizationH3+N−CH|CH2CH2COOH−COO−⟶2nd ionizationH3+N−CH|CH2CH2COO−−COO− Isoelectric poin (pI)=pKa1+pKa32 2.2+4.32=3.25

Glutamic acid $H_{2} N - C H (C H_{2} C H_{2} C O O H) - C O O H N$ has $p K_{a 1} (α - C O O H) = 2.2, p K a 2 (R g r o u p C O O H) = 4.3$ . The isoelectric point of glutamic acid is