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Gold crystall...

Question

Gold crystallizes in the FCC lattice. Calculate the approximate number of the unit cells in 2 mg of gold (atomic mass of gold is 197 u)

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Solution

197g of Gold contains 6.02210^23 gold atoms
so 2mg of gold will have x gold atoms ie
2mg/1000=0.002g6.02210^23/197 gold atoms
=6.113710^18 gold atoms .
1 unit cell of fcc lattice contains 4 atoms .
so number of unit cell =6.113710^18 divided by 4
=1.510^18 unit cells

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