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Question

good evening sir / mam

my query is that two ants are moving randomly, both started at C and managed to reach the destination point D after same time along the paths

1) average speed of the ant A is 5m/s, its average velocity is 2m/s

2) average speed of ant B is 4m/s , its average velocity is 3m/s

which of the above data is/are NOT possible

a) only 1

b) only 2

c) both

d) none

ant A moves from the path which is uneven or unequal & ant B moves along a straight line

thank you

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Solution

Average speed = fraction numerator d i s tan c e over denominator t i m e end fraction

Average velocity = fraction numerator d i s p l a c e m e n t over denominator t i m e end fraction

In question,

Case of Ant B

Ant B moves along a straight line.
That is distance = displacement.
so Average speed = Average velocity.
So statement 2 is wrong.

Case of Any A

Ant A moves from the path which is uneven or unequal.
That is distance not equal to displacement.
So Average speed not equal toAverage velocity.
But we know that distance is greaterthan displacement.So Average speed is greaterthan Average velocity.
So there is a chance to possible statement 1.

So Correct option is option b) Only 2




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