Gram molecular mass for $F e_{2} (S O_{4})_{3}$ compound is:

117.694 g

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96.18 g

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405.862 g

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96.86 g

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Solution

The correct option is A $405.862 g$
$F e - 55.85$
$S - 32$
$O - 16$
${F e}_{2} {(S O_{4})}_{3} \Rightarrow (55.85 \times 2) + (32 + (16 \times 4)) \times 3$
$= 405.862 ℊ$

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F e_{2} (S O_{4})_{3}

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