Graph between log Xm and log P is a straight line inclined at an angle θ=45∘. When pressure is 0.5 atm and log k = 0.699, the amount of solute adsorbed per g of adsorbent will be:
A
0.397 g/g adsorbent
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B
1.5 g/g adsorbent
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C
2.5 g/g adsorbent
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D
0.25 g/g adsorbent
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Solution
The correct option is C2.5 g/g adsorbent logxm=logk+1nlogPlogxm=0.699+(tan45∘)(log(0.5))logxm=0.3979=0.40xm=2.5 x=2.5 g/g adsorbent