Graphically represent the zeroes of the linear polynomial: $2 a - 14 b = 28$

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Solution

$2 a - 14 b = 28$
$2 a - 28 = 14 b$
$b = \frac{2 a - 28}{14}$
From equation (1) assume the value of $x$ and $y$ to satisfy the equation to zero.
Plotting $(14, 0), (0, - 2)$ and joining them, we get another straight line.
The graph of $2 a - 14 b = 28$ intersect the $x$ -axis at $(14, 0)$ .
Hence the zero of $2 a - 14 b = 28$ is $(14, 0)$ as it intersects at $x$ -axis at $(14, 0)$ .

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