Question

$H_{2}C=C{H}_2\stackrel{HBr}{\to }X\stackrel{hydrolysis}{\to }Y\underset{excess{I}_2}{\overset{N{a}_{2}C{O}_3}{\to }}Z$
In the given reaction, $Z$ is:

• A. $C_2{H}_{5}I$
• B. ${CHI}_3$
• C. ${CH}_{3}CHO$
• D. $C_2{H}_{5}OH$

Answer 1

The correct option is B ${CHI}_3$

The reactions that take place are:
$H_{2}C=C{H}_2\stackrel{HBr}{\to }C{H}_3-C{H}_{2}Br\stackrel{hydrolysis}{\to }C{H}_3-C{H}_{2}OH\underset{Excess/I_2}{\overset{N{a}_{2}C{O}_3}{\to }}CH{I}_3$ (Iodoform reaction)