Question

$H_2\left(g\right)+C{l}_2\left(g\right)=2HCl\left(g\right)+x$ kJ
$H_2\left(g\right)+C{l}_2\left(g\right)=2HCl\left(l\right)+y$ kJ
Then which is correct?

• A. $x>y$
• B. $x<y$
• C. $x-y=0$
• D. $x=y$

Answer 1

The correct option is A $x>y$

$\begin{array}{c}{H}_2+C{l}_2\to HCI\left(\ell \right)\to yKJ\\ H_2+C{l}_2\to HCI\left(g\right)\to xKJ\\ HCI\left(\ell \right)\to HCI\left(g\right)\to zKJ\\ x=y+zKJ\\ so,x>y\end{array}$

Option A is correct.