Question

$H_2\left(g\right)+C{l}_2\left(g\right)=2HCl\left(g\right)$;
$\Delta H\left(298K\right)=-22.06$kcal. For this reaction, $\Delta U$ is equal to:

• A. $-22.06+2\times {10}^{-3}\times 298\times 2$kcal
• B. $-22.06+2\times 298$ kcal
• C. $-22.06-2\times 298\times 4$kcal
• D. $-22.06$ kcal

Answer 1

The correct option is D $-22.06$ kcal

For a chemical reaction-

$\Delta H=\Delta E+\Delta n_{g}RT$

$\Delta E=\Delta E-\Delta n_{g}RT$

$\Delta E=-22.06Kcal$

As the $\Delta n_g=0$