$H_{2}$ gas is liberated at cathode and anode both by electrolysis of the following aq. solution except in:

N a H

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H C O O N a

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N a C l

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L i H

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Solution

The correct option is D $N a C l$
In case of $N a C l$
At anode:
$2 C l^{-} \to C l_{2} + 2 e^{-}$
At cathode:
$2 H^{+} + 2 e^{-} \to H_{2}$
So here, $C l_{2}$ liberated at anode.
In other cases, hydrides liberate hydrogen gas at anode and hydrogen ion liberates hydrogen gas at cathode.

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