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Ozone

H2+I2→ 2HIIn ...

Question

$H_{2} + I_{2} \to 2 H I$
In the reaction shown above, which substance is oxidized?

Iodine

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Hydrogen and Iodine

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Hydrogen iodide

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Hydrogen

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Solution

The correct option is C Iodine
In the given reaction oxidation state of iodine is changed from zero to $- 2$ so iodine is oxidised.

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Similar questions

H_{2} + I_{2} \to 2 H I

K_{e q}

H_{2} = 1

I_{2} = 2

H I = 3

H_{2} + I_{2} ⇌ 2 H I

2 H I ⇌ H_{2} + I_{2}

△ G_{f}^{0}

^{- 1}

H I (g)

^{- 1}

H_{2} + I_{2} \to 2 H I

\to H_{2} + I_{2}

H_{2} + F_{2} \to 2 H F

2 H F \to H_{2} + F_{2}

The equilibrium constant for the given reaction $H_{2} + I_{2} ⇌ 2 H I$ is correctly

given by expression

2 H I ⇌ H_{2} + I_{2}, K_{p}

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