$H_{2} O_{2}$ oxidises $M n O_{2}$ to $M n O_{4}^{-}$ in basic medium. $H_{2} O_{2}$ and $M n O_{2}$ react in the molar ratio of $x : y$ . What is the value of $x + y$ ?

Open in App

Solution

$3 H_{2} O_{2} + 2 M n O_{2} ⟶ M n O_{4}^{-} + 6 H_{2} O$
Thus,
$H_{2} O_{2} : M n O_{2} = 3 : 2$
So, $x + y = 3 + 2 = 5$

Suggest Corrections

Similar questions

H_{2} O_{2}

M n O_{2}

M n O_{4}^{-}

H_{2} O_{2}

M n O_{2}

H_{2} O_{2} + M n O_{4}^{-} ⟶ O_{2} + M n O_{2}

H_{2} O_{2} (a q)

{M n}^{2 +} (a q)

M n O_{2}

C l O_{2}

H_{2} O_{2}

O_{2}

{C l}^{⊖}

H_{2} O_{2}

C l O_{2}

M n O_{4}^{-} + H_{2} O_{2} \to M n O_{2} + O_{2}

Join BYJU'S Learning Program