$H_{2} O$ vapours on passing through anhydrous
$C u S O_{4}$ turns it to:

green

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blue

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violet

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Solution

The correct option is B blue
It still will be copper (II) sulfate, but it will be an equation of it due to the mixture of water. You need to know how many moles of water you are reacting with, for example
$C u S O 4 + 5 * H 2 O - - > C u S O 4.5 H 2 O$
=Copper (II) Sulfate Pentahydrate

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Similar questions

List-I	List-ll
(A) $O_{3}$	(1) Turns benzidine paper to brown
(B) Hypo	(2) Turns anhydrous ${C u S O}_{4}$ to blue
(C) $H_{2} O$	(3) Violet colour with $F e C l_{3}$
(D) $H_{2} S$	(4) Rotten egg smell

The correct match is :

Q. A certain compound on burning in air forms three oxides. One of the oxides turned lime water milky, the other turned anhydrous

C u S O_{4}

blue and third formed a solution of

p H = 9

. Compound is formed of :

C u {S O}_{4} \cdot 5 H_{2} O

is blue in colour whereas anhydrous

C u {S O}_{4}

is colourless. Why?

If $C u S O_{4 (s)}$ . $5 H_{2} O_{(s)}$ $⇋$ $C u S o_{4}$ . $H_{2} O_{(s)}$ + $2 H_{2} O$ (g) $K_{p}$ = 1.0 x $10^{- 4}$ atm2 at $250^{\circ}$ . The efflorescent nature of CuSO4 . 5H2O can be noticed when vapour pressure of H2O in atmosphere is:

Q. If

{C u S O}_{4} \cdot 5 H_{2} O (s) ⇌ {C u S O}_{4} \cdot {3 H}_{2} O (s) + {2 H}_{2} O (l) K_{p} = 1.086 \times 10^{- 4} {a t m}^{2} a t 25^{o} C

The efflorescent nature of

{C u S O}_{4} \cdot {5 H}_{2} O

can be noticed when vapour pressure of

H_{2} O

in atmosphere is:

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H2O vapours on passing through anhydrousCuSO4 turns it to:

The correct option is B blueIt still will be copper (II) sulfate, but it will be an equation of it due to the mixture of water. You need to know how many moles of water you are reacting with, for exampleCuSO4+5∗H2O−−>CuSO4.5H2O=Copper (II) Sulfate Pentahydrate

$H_{2} O$ vapours on passing through anhydrous
$C u S O_{4}$ turns it to:

The correct option is B blue
It still will be copper (II) sulfate, but it will be an equation of it due to the mixture of water. You need to know how many moles of water you are reacting with, for example
$C u S O 4 + 5 * H 2 O - - > C u S O 4.5 H 2 O$
=Copper (II) Sulfate Pentahydrate