$H_{2} O_{2}$ can be obtained when following react with $H_{2} S O_{4}$ except with:

P b O_{2}

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B a O_{2}

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N a_{2} O_{2}

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K O_{2}

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Solution

The correct option is A $P b O_{2}$
The reactions of the following compounds with $H_{2} S O_{4}$ can be given as:-
$P b O_{2} + H_{2} S O_{4} ⟶ P b S O_{4} + O_{2} + H_{2} O$
$B a O_{2} + H_{2} S O_{4} ⟶ H_{2} O_{2} + B a S O_{4}$
$N a_{2} O_{2} + H_{2} S O_{4} ⟶ N a_{2} S O_{4} + H_{2} O_{2}$
$2 K O_{2} + H_{2} S O_{4} ⟶ K_{2} S O_{4} + H_{2} O_{2} + O_{2}$
From the above reactions, it can be conducted that except $P b O_{2}$ all the compounds react with $H_{2} S O_{4}$ to give $H_{2} O_{2}$ while $P b O_{2}$ on reacting with $H_{2} S O_{4}$ gives $P b S O_{4}, H_{2} O$ and $O_{2}$ .

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Similar questions

H_{2} O_{2}

H_{2} S O_{4}

$H_{2} O_{2}$ can be obtained when following reacts with $H_{2} S O_{4}$ expect with

H_{2} O_{2} ?

B a O_{2} + H_{2} S O_{4} \to B a S O_{4} + H_{2} O_{2}

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