H 2 O 2 reduces MnO 4-ion toA- Mn 2-B- Mn 3-C- Mn -D- Mn -

The correct option is A Mn^2+2MnO^ _4+5H_2O_2+6H^+ → Mn2++5O_2+8H_2O. ...

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Byju's Answer

Standard IX

Chemistry

Oxidants and Reductants

H 2 O 2 reduc...

Question

$H_{2} O_{2}$ reduces $M n O_{4}^{-}$ ion to

M n^{+}

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M n^{2 +}

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M n^{3 +}

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M n^{-}

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Solution

The correct option is B $M n^{2 +}$
$2 M n O_{4}^{-} + 5 H_{2} O_{2} + 6 H^{+} \to M n 2 + + 5 O_{2} + 8 H_{2} O$ .

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Similar questions

Q. Equivalent weight

{M n}^{3 +}

in the following reaction is (

M n = 55

) :

{M n}^{3 +} ⟶ {M n}^{2 +} + M n O_{2}

The standard redox potential for reactions Mn²⁺+2e -----> Mn and Mn³⁺+1e -----> Mn²⁺ are 2.36 and 1.51V respectively . What is the redox potential for the reaction Mn³⁺+3e------> Mn ?

Given below are the half-cell reactions:

M n^{2 +} + 2 e^{-} \to M n; E^{0} = - 1.18 V

2 (M n^{3 +} + e^{-} \to M n^{2 +}); E^{0} = + 1.51 V

The

E^{0}

for

3 M n^{2 +} \to M n + 2 M n^{3 +}

will be:

In the reaction
$C_{2} O_{4}^{2 -} + M n O_{4}^{-} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O$ which is the reducing agent?

Q. If

(m n - 1)^{2} = (m n)^{2} + 1 + 2 y

, then y is equal to

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H2O2 reduces MnO−4 ion to

The correct option is B Mn2+2MnO−4+5H2O2+6H+→Mn2++5O2+8H2O.

$H_{2} O_{2}$ reduces $M n O_{4}^{-}$ ion to

The correct option is B $M n^{2 +}$
$2 M n O_{4}^{-} + 5 H_{2} O_{2} + 6 H^{+} \to M n 2 + + 5 O_{2} + 8 H_{2} O$ .