Question

$H_{2}O$ is a weaker field ligand than $N{H}_3$ and ${\Delta }_{oct}$ $\left(\right[Cr\left(N{H}_3{)}_6{]}^{3+}\right)<{\Delta }_{oct}\left(\right[Cr\left(H_{2}O{)}_6{]}^{3+}\right)$

• A. True
• B. False

Answer 1

The correct option is B False

$H_{2}O$ is a weaker field ligand than $N{H}_3$ so splitting will be less here and ${\Delta }_{oct}$ $\left(\right[Cr\left(N{H}_3{)}_6{]}^{3+}\right)>{\Delta }_{oct}\left(\right[Cr\left(H_{2}O{)}_6{]}^{3+}\right)$. Hence, the given statement is false.