$H_{2} S O_{4}$ can not be used to prepare HI from KI as ____________.

its reaction with KI is very slow.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

it oxidises HI to iodine.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

it disproportionates HI.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

it reduces HI.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B it oxidises HI to iodine.
$H_{2} S O_{4}$ is stronger oxidising agent and $H I$ is stronger reducing agent. So $H_{2} S O_{4}$ oxidises and get reduced to $S O_{2}$ .
$K I + H_{2} S O_{4} \to K H S O_{4} + H I$
The reaction proceed further as below:
$H I + H_{2} S O_{4} \to I_{2} + S O_{2} + 2 H_{2} O$
Option B is correct.

Suggest Corrections

Similar questions

H_{2} S O_{4}

H_{2} S O_{4}

K I

H_{2} S O_{4}

K I

I_{2}

K I

H_{2} S O_{4}

H_{2} S O_{4}

H_{2} S O_{4}

H_{2} S O_{4}

H B r

N a B r

N a B r

Join BYJU'S Learning Program