$H_{3} P O_{2}$ only forms $N a H_{2} P O_{2}$ . The equivalent weight of acid (in g) is :

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Solution

Here, $H_{3} P O_{2}$ gives only one H ion, so equivalent weight $=$ molecular weight $=$ $66$ .

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Similar questions

H_{3} P O_{2} + N a O H \to N a H_{2} P O_{2} + H_{2} O

H_{3} P O_{2}

H_{3} P O_{4} - ------ - + C a (O H)_{2} ⟶ C a H P O_{4} + 2 H_{2} O

H_{3} P O_{2} - ------ - + N a O H ⟶ N a H_{2} P O_{2} + H_{2} O

N a H C_{2} O_{4} - ---------- - + N a O H ⟶ N a_{2} C_{2} O_{4} + H_{2} O

P_{4}

P_{4} + N a O H \to N a H_{2} P O_{2} + P H_{3}

What is the equivalent weight of H3PO2

H_{3} P O_{2}

2 H_{3} P O_{2} \to H_{3} P O_{4} + P H_{3}

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