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Bond Angle

H-B-H bond an...

Question

$H - B - H$ bond angle in $B H_{4}^{-}$ is:

180^{o}

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120^{o}

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109^{o}

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90^{o}

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Solution

The correct option is D $109^{o}$
$H - B - H$ bond angle in $B {H_{4}}^{-}$ is $109^{\circ}$ because it forms the tetrahedral geometry.

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