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Question

H.C.F of two polynomials is a + 5 and L.C.M is (a +5) (a + 4 )(a -1).1f one of the polynomials is a2+4a5, then the other polynomial is

A
a2+9a20
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B
a29a+20
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C
a2+9a+20
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D
a29a20
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Solution

The correct option is C a2+9a+20
Since, LCM × HCF = 1st polynomial × 2nd polynomial
Other polynomial =LCM×HCF1st Polynomial
=(a+5)(a+4)(a1)(a+5)a2+4a5
=(a+5)(a+4)(a1)(a+5)(a+5)(a1)
=(a+4)(a+5)
=a2+9a+20
Option C is correct.

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