Question 1(h)
Solve the following equations :
6z+10=-2

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Solution

$6 z + 10 = - 2 \Rightarrow 6 z = - 2 - 10$
$\Rightarrow 6 z = - 12$
$\Rightarrow z = \frac{- 12}{6} \Rightarrow z = - 2$

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Question 1(h) :

Solve:

$\frac{5}{6} - \frac{1}{3}$

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