H2Sg - Cl2 g - 2 HClg - SsThe reaction is interpreted as

H2S: By losing hydrogen atoms, H2S is oxidized to form to S. Cl2: By obtaining hydrogen atoms, Cl2 nbsp;is reduced to HCl ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sulphuric Acid

H2Sg + Cl2 g ...

Question

$H_{2} S (g) + C l_{2} (g) \to 2 H C l (g) + S (s)$ The reaction is interpreted as

H_{2} S

is getting reduced and

C l_{2}

is getting oxidised

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Both

H_{2} S

and

C l_{2}

are reduced

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2} S

is getting oxidised and

C l_{2}

is getting reduced

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Only

H_{2} S

is oxidised

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

112 cm of $H_{2} S$ (g) is mixed with $120 c m^{3}$ (g) at STP to produce HCl(g) and sulphur (s).

Write a balanced Equation for this reaction and calculate (i) the volume of gaseous product formed (ii) composition of the resulting mixture.

H_{2} S (g) + {C l}_{2} (g) \to 2 H C l (g) + S (s)

H_{2} S (g) + C l_{2} (g) \to 2 H C l (g) + S (s)

$H_{2} S (g) + C l_{2} (g) \to 2 H C l (g) + S (s)$

The reaction is interpreted as:

Join BYJU'S Learning Program