Half-life of a chemical reaction at a given concentration is 50 minutes. When the concentration of the reactant is doubled, the half-life becomes 100 minutes. The order of the reaction is:
A
Zero
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B
One
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C
Two
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D
Three
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Solution
The correct option is A Zero Half life ∝[A]1−n T1=50min when concentration is x T2=100min when concentration is 2x T1T2=x1−n(2x)1−n 50100=(12)1−n n=0