Question

HCF of two numbers $A$ and $B$ is $24$. HCF of two other numbers $C$ and $D$ is $36$. What will be the HCF of $A,B,C$ and $D$?

• A. 12
• B. 24
• C. 36
• D. 6

Answer 1

The correct option is A 12

HCF of $A$ and $B$ $=24=2^3\times 3$

HCF of $C$ and $D$ $=36=2^2\times 3^2$

Then, HCF of $(A,B)$ and $(C,D)$ = HCF of $24$ and $36$ $=2^2\times 3=12$
[As HCF is the product of lowest powers of the common factor]