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Byju's Answer
Standard XII
Chemistry
Features of MOT
Heat evolved ...
Question
Heat evolved in the reaction
H
2
+
C
l
2
→
2
H
C
l
is
182
k
J
.
( Bond energies
H
−
H
=
430
k
J
/
m
o
l
e
,
C
l
−
C
l
−
242
k
J
/
m
o
l
e
). The
H
−
C
l
bond energy is:
A
763
k
J
/
m
o
l
e
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B
427
k
J
/
m
o
l
e
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C
336
k
J
/
m
o
l
e
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D
154
k
J
/
m
o
l
e
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Solution
The correct option is
B
427
k
J
/
m
o
l
e
1
2
H
2
+
1
2
C
l
2
⟶
H
C
l
Δ
f
H
=
Δ
H
B
E
R
e
a
c
t
a
n
t
s
−
Δ
H
B
E
P
r
o
d
u
c
t
s
−
90
=
1
2
430
+
1
2
242
- BE of HCl
BE of
H
C
l
=
215
+
121
+
90
=
426
≈
427
k
J
/
m
o
l
e
Hence the answer is
427
k
J
/
m
o
l
e
Suggest Corrections
1
Similar questions
Q.
Heat evolved in the reaction ,
H
2
(
g
)
+
C
l
2
(
g
)
→
2
H
C
l
(
g
)
is
182
k
J
. Bond energies
H
−
H
=
430
k
J
/
m
o
l
e
, and
C
l
−
C
l
=
242
k
J
/
m
o
l
e
. The
H
−
C
l
bond energy is
Q.
Heat evolved in the reaction
H
2
+
C
l
2
⟶
2
H
C
l
is 182 kJ. Bond energies pf H-H and Cl-Cl are 430 and 242 KJ/mol respectively. The H-Cl bond energy is:
Q.
Heat evolved in the reaction
H
2
+
C
l
2
→
2
H
C
l
is
182
KJ. Bond energies of
H
−
H
and
C
l
−
C
l
are
430
and
242
KJ/mol respectively.
Thus
H
−
C
l
bond energy is :
Q.
The energy required to break one mole
C
l
−
C
l
bonds in
C
l
2
is
242
K
J
m
o
l
−
1
. The longest wavelength of light capable of breaking a single
C
l
−
C
l
bond is:
Q.
Bond energies of H - H and CI - CI are
430
k
J
m
o
l
−
1
and
242
k
J
m
o
l
−
1
respectively.
Δ
H
f
for HCl is
91
k
J
m
o
l
−
1
. What will be the bond energy of H - Cl bond (per mole value)?
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