_______ + heat $⟶ K_{2} M n O_{4} + M n O_{2} + O_{2}$

$K M n O_{4}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$2 K M n O_{4}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$K_{2} M n O_{4}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$2 K_{2} M n O_{4}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
$2 K M n O_{4}$

On the product side, we have

2 K atoms, 2 Mn atoms and 8 O atoms

We know that the atoms on the reactant side should be the same as on the product side.

So, on balancing we get:

$2 K M n O_{4} + h e a t ⟶ K_{2} M n O_{4} + M n O_{2} + O_{2}$

$K M n O_{4}$ is potassium permanganate.

This is the laboratory method to prepare $O_{2}$ .

Suggest Corrections

Similar questions

M n O_{2} + 2 K C l O_{3} \to K_{2} M n O_{4} + C l_{2} + 2 O_{2}

C l_{2} + K_{2} M n O_{4} \to 2 K C l + M n O_{2} + O_{2}

Each reaction takes place to the extent of 50 %.

11.2 L of

O_{2}

at STP is obtained from

K C l O_{3}

using?

Q. The oxidation state of Mn in

K_{2} M n O_{4}

is same as that in

M n O_{2}

Q. Arrange the following in increasing order of oxidation states of

M n

K_{2} M n O_{4}, M n O_{2}, K M n O_{4}

$M n O_{2}$ when fused with KOH and oxidized in air gives a dark green compound X. In acidic X. In acidic solution, X undergoes disproportion to give an intense purple compound Y and $M n O_{2}$ . The compounds X and Y respectively, are

Q. What is the oxidation number of

M n

K M n O_{4}, K_{2} M n O_{4}, M n S O_{4}, M n O_{2}

and

{M n}_{3} O_{4}

respectively?

Join BYJU'S Learning Program

_______ + heat ⟶K2MnO4+MnO2+O2

_______ + heat $⟶ K_{2} M n O_{4} + M n O_{2} + O_{2}$