Heat of combustion of $C H_{4}$ , $C_{2} H_{6}$ and $C_{3} H_{8}$ are respectively - 210, - 368.4 and - 526.8 Kcal $m o l_{1}$ Hence, heat of combustion of $C_{8} H_{16}$ is approximately:

- 1267.2 K c a l / m o l

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- 684 K c a l / m o l

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- 840 K c a l / m o l

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- 1000 K c a l / m o l

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Solution

The correct option is A $- 1267.2 K c a l / m o l$
$C_{8} H_{16} = C H_{4} + 2 C_{2} H_{6} + C_{3} H_{8} - 3 H_{2}$
$= - 210 + 2 (- 368) + (- 526.8) - 286$
$= - 1267 K c a l / m o l$

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Enthalpy of combustion of $C H_{4}, C_{2} H_{6}$ and $C_{3} H_{8}$ are -210.8, -368.4 and -526.2 k cal $m o l^{- 1}$ respectively. Enthalpy of combustion of hexane can be predicted as ?

The heat of combustion for $C$ , $H_{2}$ and $C H_{4}$ are $- 349$ kJ/mol, $- 241.8$ kJ/mol and $- 906.7$ kJ/mol respectively. The heat of formation in kJ/mol of $C H_{4}$ is :