Heat of formation of $C O_{2}$ is $- 94.0 k c a l$ . It shows that:

C O_{2}

is exothermic compound

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C O_{2}

is endothermic compound

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C O_{2}

is isothermal compounds

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none of these

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Solution

The correct option is C $C O_{2}$ is exothermic compound
Heat of formation of $C O_{2}$ is $- 94.0 k c a l$ . It shows that
formation of $C O_{2}$ is exothermic reaction. Heat is liberated (given out) during the reaction.
Reactants $\to C O_{2} +$ heat.
Note: Negative value of enthalpy change for a reaction indicates exothermic reaction. Positive value of enthalpy change for a reaction indicates endothermic reaction.

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Similar questions

C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O,

C O_{2}

C O_{2}

C O

{C O}_{2}

{C O}_{2}

- 94.3 k c a l

C O

- 26.0 k c a l

C + O_{2} \to {CO}_{2} + Heat

{C O}_{2}

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