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Question

Heat of formation of KOH(s) using the following equations :


K(s)+H2O(l)+(aq)KOH(aq)+12H2(g);ΔH=48.0kcal

H2(g)+12O2(g)H2O(l);ΔH=68.4kcal

KOH(s)+(aq)KOH(aq);ΔH=14.0kcal

A
102.4kcal
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B
152.5kcal
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C
112.6kcal
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D
None of these
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Solution

The correct option is A 102.4kcal
Given that,
K(s)+H2O(l)+(Aq.)KOH(aq)+12H2(g);ΔH=48.0kcal ...( i)
H2(g)+12O2(g)H2O(l);ΔH=68.4kcal ...( ii)
KOH(s)+(aq)KOH(aq);ΔH=14.0kcal ...(iii)

By inspection method eqs. [(i) + (ii) - (iii)]-

K(s)+12H2(g)+12O2(g)KOH(s);ΔH=102.4kcal

Hence, option A is correct.

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