Question

Heat of neutralisation for the given reaction $NaOH+HCl\to NaCl+H_{2}O$ is $57.9kJ/mole$. What will be the heat released when 0.75 moles of $NaOH$ is titrated against 1.25 moles of $HCl$?

• A. $22.56$ kJ
• B. $47.12$ kJ
• C. $43.42$ kJ
• D. $28.65$ kJ

Answer 1

The correct option is C $43.42$ kJ

Given :
$NaOH+HCl\to NaCl+H_{2}O$
Heat of neutralization for 1 mole of $HCl$ and $NaOH$ is $57.9kJ/mole$.
Here, $NaOH$ is the limiting reagent and decides the extent of reaction.
So, heat of neutralization for 0.75 mole of reactant $NaOH$ is $0.75mol\times 57.9$ kJ/mole = 43.42 kJ