Question

Heat of neutralisation of $HCl$ against $NaOH$ is $13.7kcal{eq}^{-1}$. What will be the ionisation energy of ${CH}_{3}COOH$ in $kcal$ ${mol}^{-1}$ if its heat of neutralisation is $11.7kcal{eq}^{-1}$?

• A. 4
• B. 2
• C. 6
• D. 8

Answer 1

Answer: (B)

2

The heat of neutralisation of strong acid and strong base is $13.7kcale{q}^{-1}$, and the heat of neutralisation of weak acid and strong base is $11.7kcale{q}^{-1}$,

so, the extra amount of heat is used up in the ionisation of $C{H}_{3}COOH$

so, ionisation energy = $13.7-11.7=2kcale{q}^{-1}$