CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

Heat of Neutralisation of strong Acid and strong base is 57 KJ. The amount of heat released when 0.5 mole of HNO3 solution is added to 0.2 mole of NaOH solution is


A

11.40 KJ

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

57 KJ

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

28.5 KJ

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

34.9 KJ

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

11.40 KJ


Here 0.2 mole of NaOH is limiting Regent. So, neutralisation of one mole of NaOH release heat = 57 KJ.

Neutralisation of 0.2 mole of NaOH release heat = 57 × 0.2 = 11.40 KJ.


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Reactions in Solutions
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon