Question

Heat of neutralization of strong acid against strong base is constant and is equal to

• A. $13.7kcal$
• B. $57kJ$
• C. $5.7\times {10}^{4}J$
• D. All of the above

Answer 1

The correct option is D All of the above

$13.7kcal=57kJ=5.7\times {10}^{4}J$