Heat of reaction for the change Zn+Cu2+(0.1M)→Zn2+(1M)+Cu at 27oC is:
A
−2.17×105J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
−2.29×105J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
−2.24×105J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
−1.84×105J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A−2.17×105J The relationship betwen standard emf and standard cell potential is E0=−ΔH0nF+T(dEdT)P Substitute values in the above reaction. 1.085=−ΔH02×96500+300×(1.4×10−4)ΔH0=−2.17×105