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Effect of High Latent Heat of Fusion of Ice

Heat required...

Question

Heat required in converting 1 g of ice at -10 $^{0} C$ into steam at 100 $^{0} C$ is

3.03 KJ

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6.05 KJ

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0.721 KJ

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0.616 KJ

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Solution

The correct option is A 3.03 KJ
1 g ice $Q_{1} - \to$ ice $Q_{2} - \to$ water $Q_{3} - \to$ water $Q_{4} - \to$ steam $Q_{5} - \to$
$Q_{1} = m c △ T$
$= 2.1 \times 10$
$= 21 J$
$Q_{2} = m l$
$= 1 \times 334$
$= 334 J$
$Q_{1} = m c △ T$
$= 1 \times 4.18 \times 100$
$= 418 J$
$Q_{2} = m l$
$= 1 \times 2257$
$= 2257 J$
$Q = Q_{1} + Q_{2} + Q_{3} + Q_{4}$
$= 3030 J$

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